APPLYING ANOVA TO SHOW THAT POSITIONING OF LO IS INDEPENDENT OF SHAPE OF LO

Case 1 : LO is a circle

Case 2 : LO is a rectangle

Case 3 : LO is a square

Case 4 : LO is a triangle

ANOVA TABLE	CASE 1	CASE 2	CASE 3	CASE 4
NUM_EL	47	47	47	47
SUM_OF_EL	19310	18982	19612	19229
MEAN	411	404	417	409
(SUM_OF_EL)^2 BY NUM_EL	793334	7666305	8183629	7867116
SUM_OF_EL_SQ	8335952	8300198	8487520	8189157

Also,
N = 188 = total number of elements
K = 4 = total number of different cases
T = 77133 = sum of all elements
T*T/N = 31646274
TSQ = 33312784 = Total sum of SUM_OF_EL_SQ
TSTbyN = 31650584 = total sum of (SUM_OF_EL)^2 BY NUM_EL

Between = TSTbyN - T*T/N
Within = TSQ - TSTbyN

V1 = Variance estimate between cases = Between / ( K - 1 )
V2 = Variance estimate within cases = Within / ( N - K )

F-ratio = V1 /V2 = 0.159034

For the given values of N and K, the value of the F-ratio required for rejection of the null hypothesis is 4.71
As the F-ratio is less than the maximum allowed value, the null hypothesis can be assumed to be validated.

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